The vapour pressure of chloroform `(CHCl)_(3)` and dichlorocethene `(CH_(2)Cl_(2))` at `298 K` is `200 mm Hg ` and `415 mm Hg`, respectively. Calculate
a. The vapour pressure of the solution prepared by mixing `25.5 g` of `CHCl_(3)` and `40 g` of `CH_(2)_Cl(2)` at `298 K`.
b. Mole fractions of each components in vapour phase .

Explanation

Calculation of vapour pressure of solution.
`"Molar mass of" CH_(2CI_(2))=12xx1+1xx2+35.5xx2=85 g mol^(-1)`
`"Molar mass of "CHCI_(3)=12xx1+1xxxx1+35.5xx3=119.5 g mol^(-1)`
`"Moles of "CHKI_(3)(n_(B))=((25.5g))/((119.5gmol^(-1)))=0.213 mil`
`"Moles" CH_(2)CI_(2)(n_(A))=((40.0g))/((85.0g mol^(-1)))=0.47 mol`
Total number of moles = 0.213+0.47= 0.683 mol
`"Mole fraction of" CH_(2)CI_(2)(n_(A))=(0.47 mol)/(0.683 mol)=0.312 `
` "Vapour pressure of solution" (P)=P_(A)+P_(B)=P_(A)(^(@)x_(A)+P_(B)^(@)x_(B)`
` =(145mm)xx0.688+(200mm)x(0.321)`
`(285.52+62.40)=347.92 mm.`
`"Calculation of vapour pressure of each component in the capour phase. Let the mole fraction of each component in the capour phase be"(x_(A))and (x_(B)).`
`"Their patial pressures are"P_(A) and P_(B).`
` "Mole fraction of "C_(2)H_(2)CI_(2)" in the capour phase" x_(A)=P_(A)/(P_(A)+P_(B))=((62.40 mm))/((347/92mm))=0.18`