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A solution prepared by dissolving 1.25g ...

A solution prepared by dissolving `1.25g` of oil of winter green (methyl sallicylate) in `99.0g` of benzene has a boiling point of `80.31^(@)C`. Determine the molar mass of this compound. (`B.P.` of pure benzene `=80.10^(@)C` and `K_(b)` for benzene `=2.53^(@)C kg "mol".1`)

Text Solution

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`M_(B)=(K_(b)xxW_(B))/(DeltaT_(b)xxW_(A))`
`K_(b)=2.53 K kg mol^(-1),W_(B)=1.25g, W_(A)=99.0g=0.099 kg, DeltaT_(b)=(80.31-80.10)=0.21^(@)=0.21K`
`M_(B)=((2.53K kgmol^(-1))xx(1.25g))/((0.21K)xx(0.099 kg))=152.12 g mol^(-1)`
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