An aqueus solution freezes at 272.07 K while pure water freezes at 273 K. Determine the molality and boiling point of the solution. Given `K_(f)=1.86 K//m, K_(b)=0.512 K//m.`

Explanation

To solve the problem of determining the molality and boiling point of the solution, we can follow these steps:

### Step 1: Calculate the change in freezing point (ΔTf)
The freezing point of pure water (T0f) is 273 K, and the freezing point of the solution (Tf) is 272.07 K.

\[ \Delta T_f = T_0f - T_f = 273 \, \text{K} - 272.07 \, \text{K} = 0.93 \, \text{K} \]
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