Calculate the amount of `CaCI_(2) ("molar mass"=111 g mol^(-1))` which must be added to 500 g of water to lower its freezing point by 2 K assuming `CaCI_(2)` to be completely dissoviated `(K_(f) for = 1.86 "K kg mol"^(-1))`.

Explanation

To solve the problem of calculating the amount of \( \text{CaCl}_2 \) needed to lower the freezing point of water by 2 K, we will follow these steps:

### Step 1: Understand the given data
- Depression in freezing point (\( \Delta T_f \)) = 2 K
- Molar mass of \( \text{CaCl}_2 \) = 111 g/mol
- \( K_f \) for water = 1.86 K kg/mol
- Mass of water = 500 g = 0.5 kg

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