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An aqueous solution sntaining 1.248 g of...

An aqueous solution sntaining 1.248 g of barium chloride `("molar mass"= 208.34 g mol^(-1))` in 100 g of water boils at `100-0832^(@)C`. Calculate degree of dissoviation of barium of barum choride `(K_(b)"for water"=0.52 K kg mol^(-1))`

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To solve the problem of calculating the degree of dissociation of barium chloride (BaCl₂) in an aqueous solution, we will follow these steps: ### Step 1: Calculate the molality of the solution 1. **Given data**: - Mass of BaCl₂ = 1.248 g - Molar mass of BaCl₂ = 208.34 g/mol - Mass of water (solvent) = 100 g = 0.1 kg ...
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