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Calculate the freezing point depression ...

Calculate the freezing point depression expected for `0.0711` m aqueous solution of `Na_(2)SO_(4)` . If this solution actually freezes at `-0.320 ^(@)C` , what would be the value of Van't Hoff factor ?
(`K_(f)` for water is `1.86 ^(@)C mol^(-1)`) .

Text Solution

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Calculate of normal value of `DeltaT_(f)`
`(DeltaT_(f)=K_(f)xxm)`
`K_(f)=1.86^(@)C mol^(-1)=1.86 K kg mol^(-1)`,
`m=0.011 molkg^(-1)`
`DeltaT_(f)=(1.86 Kkg mol^(-1))xx(0.0711 mol kg^(-1))=0.132 K`
Calcution of Van't Hoff factor
`"Van't Hoff factor "(i)=("Actual value of"DeltaT_(f))/("Noraml value of"DeltaT_(f))`
Actual valur of `DeltaT_(f)=0-(-00.320)=0.320^(@)C=0.320 K`
`i=((0.320K)/(0.132K))=242`
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