Calculate the freezing point of a solution when 3 g of `CaCI_(2) (M=111 g mol^(-1))` was dissolved in 100g of water assuming that `CaCI_(2)` undergoes complete ionisation `(K_(f) "for water"=1.86 K kg mol^(-1))`.

Explanation

To calculate the freezing point of a solution when 3 g of \( \text{CaCl}_2 \) is dissolved in 100 g of water, we can follow these steps:

### Step 1: Calculate the number of moles of \( \text{CaCl}_2 \)

The molar mass of \( \text{CaCl}_2 \) is given as 111 g/mol.

\[
\text{Number of moles} = \frac{\text{mass of solute}}{\text{molar mass}} = \frac{3 \, \text{g}}{111 \, \text{g/mol}} \approx 0.0270 \, \text{mol}
...