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H(2)S, a toxic gas with rotten egg like ...

`H_(2)S`, a toxic gas with rotten egg like smell, is used for the qualitative analysis.If the solubility of `H_(2)S` in water at `STP` is `0.195 m`, calculate Henry's law constant.

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Calculate of mole fractiion of `H_(2)S`
By difinition, 0.195m of the gas means that 0.195 mole of it is dissolved in 1000 g of water.
No. of moles of water in 1000 g= `((1000g))/((18g mol^(-1)))=55.55 mol`
Mole fraction of `H_(2)S(x_(H_(2)S))=(n_(H_(2)S))/(n_(H_(2)S+n_(H_(2)O)))=((0.195 mol))/((0.195+55.55)mol)`
`=((0.195 mol))/((55.745 mol))=0.035`
Calculation of Henery's Law constant
According Henry's Law,
`x_(H_(2)S)=("Partial pressure of"H_(2)S)/(K_(H)"for"H_(2)S)at S.T.P.`
`K_(H)"for"H_(2)S=((0.987 "bar"))/((0.0035))=282"bar"`
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