Calculate the osmotic pressure in pascals exerted by a solution prepared by dissolving `1.0g` of polymer of molar mass `185,000` in `450mL` of water at `37^(@)C`.

Explanation

Osmotic pressure `(pi)=CRT=(W_(B)xxRxxT)/(M_(B)xxV)`
Mass pf [puert `(W_(B))`=1.0 g
Molar mass of polymer `(M_(B))` =185,00 g `mol^(-1)`
Volume of solution (V)=450 mL =0.450 L
Temperature (Y)=37+273=310 K
Solution constant ®`=8.314xx10^(3) Pa L K^(-1) mol^(-1)`
`thereforepi=((1.0g)xx(8.314xx10^(3)Pa L K^(-1))xx(310K))/((185,000 g mol^(-1))xx(0.450 L))=30.96 Pa`