If the solubility product of `CuS` is `6xx10^(-16)`, calculate the maximum molarity of `CuS` in aqueous solution.

Explanation

Dissociation of CuS in aqueous solution is:
`CuS(s)overset(aq)hArrCu^(2)(aq)+S^(2-)(aq)`
`CuS(s)overset(aq)hArrunderset([S])(Cu^(2+))(aq)+S^(2-)underset([S])((aq))`
Solubility product `(K_(sp))=[Cu^(2+)(aq)][S^(2-)(aq)]=[S]xx[S]`
`[S]=(K_(sp))^(1//2)=(6xx10^(-16))^(1//2)=2.45xx 10^(-8)M`
By definition, `K_(sp)` correponds to the product of ionic concentration of the salt in saturated solution and it represents maximum molarity of the saly. Therefore, maximum molarity of the salt= `2.45xx10^(-8)M`.