What will happen when red blood corpuscles `(RBC_(s))` ae placed in (a) 1% NaCI solution (b) 0.6% NaCI solution ?

Explanation

We all know that `RBC_(s)` are isotonic with 0.9% Naci solution.
If `RBC_(s)` are placed in contact with 1% NaCI solution, then the osmotic pressure of 1% NaCI will be higher than thet of `RBC_(s)`. As a result, water present inside the call moves into the NaCI solution through cell walls acting as semi-permeable membrane. The `RBC_(s)` will therefore, shrink.
However, reverse will take place in case these are kept in contact with 0.6% NaCI solution which has less osmotic pressure. Water will now move into the `RBC_(s)` and they will swell.
Keeping this in view, the injectable medicines are generally dissolved in saline water (0.9% NaCI solution) before being injected. This prevants the cell walls form either undergoing thrinkage or bursting.