In the determination of molar mass of `A^(+)B(-)` using colligative property, what will be the Van't Hoff factor if the solute is 40% dissociated ?

Explanation

To determine the Van't Hoff factor (i) for the electrolyte \( A^+B^- \) when it is 40% dissociated, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Dissociation**:
The electrolyte \( A^+B^- \) dissociates into two ions: \( A^+ \) and \( B^- \). When it dissociates, it produces 1 mole of \( A^+ \) and 1 mole of \( B^- \), resulting in a total of 2 moles of ions from 1 mole of the electrolyte.

2. **Degree of Dissociation**:
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