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6.02xx10^(20) molecules of urea are pres...

`6.02xx10^(20)` molecules of urea are present in `100 mL` solution. The concentration of urea solution is:

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The correct Answer is:
0.6 g `L^(-1)`
`"Mass of urea"=(6.02xx10^(20))/(6.02xx10^(23))xx(60g)=0.06 g`
`"Concentration of solution"=("Mass of urea")/("Volume of solution in litres")`
`=((0.06g))/((0.1L))=0.6 gL^(-1)`
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