Cancerntrated `HNO_(3)` used in the laboratory is usually 69% by mass of `HNO_(3)`. The density of `HNO_(3)`. The density of `HNO_(3)` solution is 1`.41 g `cm^(3)`. Find The molarity.

Answer

15.44 M

Explanation

`"Mass of solution"= 100 g, "Mass os "HNO_(3)=69 g`
`"Volume of solution"=(100 g)//(1.41" g cm"^(-3))=70.92 cm^(3)=0.07092 dm^(3)`
`"Molar mass of "HNO_(3)=1 +14 +3xx16=63" g mol"^(-1)`
`"Molarity of solution (M)"=("Mass of"HON_(3)//"Molar mass")/("Volume of solution in dm"^(3))=((69g)//(63" g mol"^(-1)))/((0.07092" dm"^(3)))`
`=15.44" mol dm"^(-3)=15.44 M`.