Determine the molaarity of an antifreeze soliution sontaining 250 g water mixed with 222 g of ethylene glylene glycol `(HOCH_(2)CH_(2)OH)`. The dnesity of solution is 1.07 g/mL.

Answer

8.12 M

Explanation

Mass of ethylene glycol = 222 g
Mass of water = 250 g
Mass of solution = (222+250)=472 g
Density of solution = 1.07 g `mL^(-1)`
`"Volume of solution (M) "=("Mass os ethylene glycol/molar mass")/("Volume os solution in litres")`
`=((222g))/((62" g mol"^(-1))xx(0.4412L))`
=8.12 mol `L^(-1)`=8.12 M