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Calculate the molarity of 9.8% (W/W) sol...

Calculate the molarity of 9.8% (W/W) solution of `H_(2)SO_(4)` if the density of solution is 1.02 g `mL^(-1)` (Molar mas of `H_(2)SO_(4)=98 g mol^(-1))`.

Text Solution

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The correct Answer is:
1.02 M
`"Molar mass of solute" (H_(2)SO_(4))=98" g mol"^(-1)`
Mass of solution = 100 g
Mass of solute = 9.8 g
`"Density of the solution" = 1.02 " g mL"^(-1)`
`"Volume of the solution"=("Mass of solution")/("Density of solution")`
`=((100g))/((1/02"g mL"^(-1))=98.04 mL = 0.098 L.`
`"Molarity of solution (M)"=("Mass os solute/Molar mass of solute")/("Volume of solution in litres")`
`((9.8g)//(98" g mol"^(-1)))/((200//1000)L)=0.5 mol L^(-1)=1.02 M.`
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