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The vapour pressure of pure liquid A is ...

The vapour pressure of pure liquid A is 40 mm Hg at 310 K. The Vapour pressure of this liquid in solution with liquid with liquid B is 32 mm Hg. Calculate the mole fraction of A in the solution if the mixture obeys Raoult's Law.

Text Solution

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The correct Answer is:
0.8
`"Vapour pressure of pure liquid A "(P_(A)^(@))=40mm.`
`"Vapour pressure of A in the solution "(P_(A))=32 mm.`
`"According to Raoults's Law" , X_(A)=P_(A)/P_(A)^(@)=((32mm))/((40mm))=0.8`
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