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30 g of urea (M=60 g mol^(-1)) is dissol...

30 g of urea (M=60 g `mol^(-1)`) is dissolved in 864 g of water. Calculater the vapour pressure of water for this soution if vapour pressure of pure waer at 298 K is 23.8 mm Hg.

Text Solution

Verified by Experts

The correct Answer is:
23.55 mm
According to Raoult's Law
`(P_(A)^(@)-P_(S))/P_(S)=W_(B)/M_(B)xxM_(A)/W_(A)`
`((23.8mm)-P_(S))/P_(S)=((30g)xx(18" g mol"^(-1)))/((60" g mol"^(-1))xx(846 g))=0.0106`
`(23.8 mm)-P_(S)=0.02106xxP_(S)`
`(23.8 mm)=1.0106xxP_(S)`
`P_(S)=((23.8 mm))/(1.0106)=23.55mm`
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