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A solution containing 0.45 g of urea in ...

A solution containing 0.45 g of urea in 22.50 g of water gave a boiling point elevation of 0.17 K. Calculate the molal biling point elevation constant for water. Molar mass of urea is 60 g `mol^(-1)`

Text Solution

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The correct Answer is:
0.51 K kg `mol^(-1)`
`DeltaT_(b)=0.17 K, W_(A)=22.50 g=0.0225 Kg, W_(B)=0.45 g,`
Mol. Mass of urea `(NH_(2)CONH_(2)), M_(B)=" g mol"^(-1), K_(b)=?`
`DeltaT_(b)=(K_(b)xxW_(B))/(W_(A)xxW_(A))`
`K_(b)=(DeltaT_(b)xxW_(A)xxM_(B))/W_(B)=((0.17 K)xx(0.0225kg)xx(60" g mol"^(-1)))/((0.45 g))=0.51" K kg mol"^(-1).`
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