Home
Class 12
CHEMISTRY
A solution of 1.25 g of a certain non-el...

A solution of 1.25 g of a certain non-electrolyte in 20.0 g of water freezes at 271.94 K. Calculate the molecular mass of the solute, `K_(f)` for water is 1.86 K/m.

Text Solution

Verified by Experts

The correct Answer is:
109.67 g `mol^(-1)`
`W_(B)=1.25g, W_(A)=0.02 kg, K_(f)-=1.86" K kg mol"^(-1),T_(f)^(@)=273 K`
`T_(f)=271.94 K, DeltaT_(f)=273-271.94=1.06 K, M_(B)=?`
`M_(B)=(K_(f)xxW_(B))/(DeltaT_(f)xxW_(A))=((1.86" K kg mol"^(-1))xx(1.25 g))/((1.06 K)xx(0.02 kg))=109.67" g mol"^(-1).`
Promotional Banner

Similar Questions

Explore conceptually related problems

A solution of 1.25g of a certain non-volatile substance in 20g of water freezes at 271.94K. Calculate the molecular mass of the solute (K_(f)=1.86" K kg mol"^(-1)) .

A solution containing 18 g of a non - electrolytic solute in 200g of H_(2)O freezes at 272.07 K . Find the molecular mass of the solute . ( K_(f) = 1.86 Km^(-1) ).

A solution containing 6.35g of a non electrolyte dissolved in 500 g of wate freezes at -0.465^(@)"C". Determine the molecular weight of the solute. ["K"_("f")"for water 1.86"^@)"C"//"m"]