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A solution containing 62.5 g of non-vola...

A solution containing 62.5 g of non-volatile solute per 1000 g of water hass a greezing point `1.06^(@)C` less than tha of water. Calculate the molecular mass of the solute. (`K_(f)`=1.86 K kg `mol^(-1)`)

Text Solution

Verified by Experts

The correct Answer is:
109.76 g `mol^(-1)`
`W_(B)=62.5g, W_(A)=1 kg, DeltaT_(f) =1.06^(@)C=1.06 K`
`K_(f)=1.86" K kg mol"^(-1), M_(B)=?`
`M_(B)=(K_(f)xxW_(B))/(DeltaT_(f)xxW_(A))=((1.86" K kg mol"^(-1))xx(62.5 g))/((1.06 K)xx1Kg)=109.67" g mol"^(-1)`
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