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A solution containing 25.6 g of sulphur,...

A solution containing `25.6 g` of sulphur, dissolved in `1000 g` of naphthalene whose melting point is `80.1^(@)C` gave a freezing point lowering of `0.680^(@)C`. Calculate the formula of sulphur (`K_(f)` for napthalene =`6.8 K m^(-1)`)

Text Solution

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The correct Answer is:
`S_(8)`
`W_(B)=25.6g, W_(A)=1 kg, DeltaT_(f)=0.68K, K_(f)=6.8" k kg mol"^(-1)`
`M_(B)=(K_(f)xxW_(B))/(DeltaT_(f)xxW_(A))=((6.8" K kg mol"^(-1))xx(25.6 g))/((0.68K)xx(1kg))=256" g mol"^(-1)`
`"Atomicity of sulphur"=((256" g mol"^(-1)))/((32" g mol"^(-1)))=8`
`"Therefore, molecular fomula of sulphur"=S_(8)`.
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