Osmotic pressure of a solution containing 2 g dissolved protain per `300cm^(3)`id solution is 20 mm of Hg at `27^(@)C`. Calculate the molecular mass of protein. (R=0.082 L atm `K^(-1)mol^(-1)`)

Answer

6238.6 h `mol^(-1)`

Explanation

`W_(B)=2.0g, V=300 cm^(3)=300 mL=0.3 L`
`pi=20" mm of Hg"=20/760=0.02632" atm, "R=0.0821" L atm K"^(-1)mol^(-1)`
`T=27^(@)C=27+273=300K, M_(B)=?`
`M_(B)=(W_(B)xxRxxT)/(pixxV)=((2.0g)xx(0.0821"L atm K"^(-1)mol^(-1))xx(300K))/((0.02632 atm)xx(0.3 L))=6238.6"g mol"^(-1)`.