Home
Class 12
CHEMISTRY
Calculate the osmotic pressure of a sout...

Calculate the osmotic pressure of a soution obtained by mixing `100cm^(3)` of 0.25 M solution of urea and `100cm^(3)` of 0.1 M solution of cane sugar at 298 K

Text Solution

Verified by Experts

The correct Answer is:
4.28 atm

`"No. of moles of urea"=(0.25" mol")xx((100cm^(3)))/((1000cm^(3)))=0.025 mol`
`"No. of moes of cane sugar"=(0.1"mol")xx((100cm^(3)))/((1000cm^(3)))=0.01 mol`
`"Total no. of moles of solutes"=(0.025+0.01)=0.035 mol`
`"Total volume of the solution"=200/1000=0.2 L`
`"Osmotic pressure "(pi)=(n_(B)RT)/V=((0.035mol)xx(0.0821"L atm K"^(-1)mol^(-1))xx(298K))/((0.2L))=4.28 atm.`
Promotional Banner

Similar Questions

Explore conceptually related problems

Calculate the osmotic pressure of a solution obtained by mixing 100 cm^(3) of 1.5% solution of urea (mol. Mass=60) and 100 cm^(3) of 3.42% solution by cane sugar (mol. Mass = 342) at 20^(@)C . (R=0.082 litre atm/deg/mole)

Calculte the osmotic pressure os a solution obtained by mixing 100 mL of 4.5% solution of urea (mol. Mass =60) and 100 mL pf 3.42% solution of cane sugar (mol. Mass =342) at 300 K. (Given R=0.0821 L atm K^(-1) mol^(-1))

What is the osmotic pressure of a solution made by mixing 100 mL of 0.1 M acetone and 100 mL of 0.2M fructose solution at 30^@C ?

Calculate the osmotic pressure of 5% solution of cane sugar (sucrose) at 300 K .

Osmotic pressure of a solution obtained by mixing 100 mL of 1.4% solution of urea (mol mass = 60) and 100 mL of 3.42% of cane sugar solution (mol mass = 342) at 20^(@)C (R = 0.0821 L atm K^(-1) mol^(-1))

Calculate osmotic pressure of a solution obtained by mixing 100 mL of 3.4% solution "(weight/volume)" of urea "(molecular weight 60)" and 100 mL of 1.6% solution "(weight/volume)" of cane sugar "(molecular weight 342)" at 20^(@)C .