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A solution containing 7.45 g of KCI per ...

A solution containing 7.45 g of KCI per litre of solution has an osmotic pressure of 4.68 atm 300 K. Calculate the degree of dissociation of KCI in solution.

Text Solution

Verified by Experts

The correct Answer is:
0.9
Calculation of observed molar mass of KCI
`"According to Van't Hoff equation ":M_(B)=(W_(B)RT)/(piV)`
`W_(B)=7.45g, pi=4.68 atm, V=1 L, T=300 K, R= 0.0821" L atm K"^(-1)mol^(-1)`
`M_(B)=((7.45g)xx(0.0821"L atm K"^(-1)mol^(-1))xx(300K))/((4.68" atm")xx(1L))=39.2" g mol"^(-1)`
Step II. Calculation of Van't Hoff factor
`i=("Normal molar mass")/("Observed molar mass")=((74.5"g mol"^(-1)))/((39.2"g mol"^(-1)))=1.9`
Step III. `"Calculation of degree of dissociation "(alpha)`
`alpha=(i-1)/(n-1)=(1.9-1)/(2-1)=0.9=0.9xx100=90%`.
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