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Osmotic pressure of a 0.0103 molar solut...

Osmotic pressure of a 0.0103 molar solution of an electrolyte was found to be 0.70 atm at `27^(@)C`. Calculate Van't Hoff factor.

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The correct Answer is:
3
`"Osmotic pressure"(pi)= I R C T`
`pi=0.70" atm",C=0.0103" mol L"^(-1), R=0.0821" L atm K"^(-1)mol^(-1)`
`T=27+273=300 K`
`i=pi/(CRT)=((0.70"atm"))/((0.0103" mol L"^(-1))xx(0.0821"L atm K"^(-1)mol^(-1))xx(300K))=2.76~~3`.
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