Home
Class 12
CHEMISTRY
Calculate the boiling point elevation fo...

Calculate the boiling point elevation for a solution prepared by adding 10 g of `CaCI_(2)` to 200 g of water. (`K_(b)` for water = 0.512 K kg mol, Molar mass of `CaCI_(2) = 100 g mol^(-1)`).

Text Solution

Verified by Experts

The correct Answer is:
0.69 K
`CaCI_(2)" dissociates in aqueous solution"`
`CaCI_(2)(s)overset(("aq"))toCa^(2+)("aq")+2CI^(-)("aq")`
`i=3, W_(B)=10 g, W_(A)=200 g= 0.2, K_(b)=0.512" K kg mol"^(-1)`
`M_(B)=110" g mol"^(-1)`
`DeltaT_(b)=ixxK_(b)m=(ixxK_(b)xxW_(B))/(M_(B)xxW_(A))`
`DeltaT_(b)=((3)xx(0.512" K kg mol"^(-1))xx(10g))/((110" g mol"^(-1))xx(0.2 kg ))=0.69 K`
Promotional Banner

Similar Questions

Explore conceptually related problems

Calculate the boiling point of a solution prepared by adding 15.00 g of NaCl to 250 g of water . (K_(b) = 0.512 K kg mol^(-1) and molar mass of NaCl = 58.44 g mol^(-1) )

The elevation in boiling point of a solution of 9.43 g of MgCl_2 in 1 kg of water is ( K_b = 0.52 K kg mol^(-1) , Molar mass of MgCl_2 = 94.3 g mol^(-1) )

Calculate the freezing point of a solution containing 60 g glucose (Molar mass = 180 g mol^(-1) ) in 250 g of water . ( K_(f) of water = 1.86 K kg mol^(-1) )