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One litre of an aqueoous solution contai...

One litre of an aqueoous solution contains 15 g of the solute of molar mass 150 g `mol^(-1)`. If the density of solution is 1.005 g/mL, calculate the mole fraction of the solute.

Text Solution

Verified by Experts

The correct Answer is:
0.00181
`"Mass of one litre (1000 mL) of solution " = "Volume"xx"Density"=1000 mLxx1.005" g mL^(-1)=1005 g`
Mass of the solute in the solution = 15 g
Mass of the solvent (water) in the solution=(1005-15)=990 g
`"No. of moles of the solute "(n_(B))=((15g))/((150"g mol"^(-1)))=0.1mol`
`"No. of moles of the solvent"(eta_(A))=((990g))/((18"g mol"^(-1)))=55mol`
`"Mole fraction of the solute"(x_(B))=n_(B)/(n_(B)+n_(A))=((0.1 mol))/((55.1 mol))=0.00181.`
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