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An aqueous solution of NaCI is marked 10...

An aqueous solution of NaCI is marked 10% W/W on the borrle. The density of soution is 1.071 g `mL^(-1)`. Calculate its molarity.

Text Solution

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The correct Answer is:
1.83 M
`"Mass of solution"=100g," Mass of NaCI"=10 g`
`"Density of soluion "1.071" g mL"^(01)`
`"Volume of 100 g of solution"= ("Mass of solution")/("Density of solution")=((100g))/((1.071" g mL"^(-1)))=93.37mL`
`"Molarity of solution (M)"=("Mass of solute/Molar mass of solute")/("Volume of solution in litres")`
`=((10g))/((58.5"g mol"^(-1))xx0.0934L)=1.83" mol L"^(-1) or 1.83 M`
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