A solution is made by dissoving 40.5 g of `C_(2)H_(5)OH` until the total volume of the solution is 100 mL. What is the percentage volume of `C_(2)H_(5)OH`? The density of pure `C_(2)H_(5)OH` is 0.78 g/mL.

Answer

51.92% m

Explanation

`"Intial mass of "C_(2)H_(5)OH=40.5 g.`
`"Density of "C_(2)H_(5)OH=0.78 g//mL.`
`"Intial volume of solution "="Mass"/"Density"=((40.5g))/((0.78g//mL))=51.92 mL`
Final volueme of solution = 100 mL
`"Precentage volume of "C_(2)H_(5)OH=("Intial volume")/("Final volume")xx100=((51.92mL))/((100mL))xx100=51.92%`