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An aqueous solution freezes at -0.186^...

An aqueous solution freezes at
`-0.186^(@)C (K_(f)=1.86^(@)` ,`K_(b)=0.512^(@)`. What is the elevation in boiling point?

A

0.186

B

0.512

C

0.86

D

0.0512.

Text Solution

Verified by Experts

The correct Answer is:
d
For the same solution
`(DeltaT_(b))/K_(b)=(DeltaT_(b))/K_(f)`
of `DeltaT_(b)=(DeltaT_(f))/(T_(f))xxK_(b)`
`=((0.186^(@)C))/1.86xx0.512.`
=`0.0512^(@)C`
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