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The density of 2.0 M solution of a solut...

The density of 2.0 M solution of a solute is `1.2 g mL^(-1)`. If the molecular mass of the solute is `100 g mol^(-1)`, then the molality of the solution is

A

2.0 m

B

1.2 m

C

0.6 m

D

2.4 m.

Text Solution

Verified by Experts

The correct Answer is:
a
Volume of solution containing 2 moles of solute =1L =1000 mL
mass of solution =`Vxxd`
=`1000mL xx1.2 g mL^(-1)=1200 g`
Molality of solvent =1000 g=1.0 kg.
`"Molality of solution (m)"=("No. of moles of colute")/("Mass of solvent in kg")`
`=((2 moles))/(1 kg)=2 "mol kg"^(-1)=2.0 m`
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