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1.0 g of a non-electolyte solute (molar ...

1.0 g of a non-electolyte solute (molar mass 250 g `mol^(-1)`) was dissolved in 51.2 g of benzene. If the `K_(f)` for benzene is 5.12 K kg `mol^(-1)`, the freezing point of benzene will be lowerd by :

A

0.2 K

B

0.4 K

C

0.3 K

D

0.5 K.

Text Solution

Verified by Experts

The correct Answer is:
b
`DeltaT_(f)=(K_(f)xxW_(B))/(M_(B)xxW_(A))`
`=((5.12 kg mol^(-1))xx(1.0g))/((250gmol^(-1))xx(0.0512kg))=0.4 K`
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