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A 5% solution (by mass) of cane sugar in...

A `5%` solution (by mass) of cane sugar in water has freezing point of 271 K. Calculate the freezing point of a 5% glucose (by mass) in water. The freezing point of pure water is 273.15 K.

A

271 K

B

273.15

C

269.07 K

D

277.23 K.

Text Solution

Verified by Experts

The correct Answer is:
c
For both the solution `W_(B)andW_(A)` are the same.
`(DeltaT_(f(g)))/(DeltaT_(f(s)))=(M_(("suorse")))/(M_(("glucose")))`
`DeltaT_(f(g))=((342g mol^(-1)))/((182g mol^(-1)))xx215K=4.04 K`
`"f.p. of glucose solution"=(273.15-4.-4)`
=269.11 K.
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