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200 mL of an aqueous solution of a prote...

200 mL of an aqueous solution of a protein contains its 1.26g. The osmotic pressure of this solution at 300K is found to be `2.57 xx 10^(-3)` bar. The molar mass of protein will be `(R = 0.083 L bar mol^(-1)K^(-1))`

A

51022 g `mol^(-1)`

B

122044 g `mol^(-1)`

C

31011 g `mol^(-1)`

D

61038 g `mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
d
According to Van't Hoff equation
`M_(B)=(W_(B)xxRxxT)/(pixxV)`
`=((1.26g)xx(0.083"L bar"mol^(-1)K^(-1))xx(300K))/((2.57xx10^(-3)"bar")xx(0.2 L))`
`=61038 g mol^(-1)`
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