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The vapour pressure of a solvent at 293 ...

The vapour pressure of a solvent at 293 K is 100 mm Hg. The vapour pressure of a solution containing 1 mole of strong electrolyte `(AB_(2))` in 99 moles of the solvent at 293 K is (assume comlete dissociation of the solute).

A

103 mm Hg

B

99 mm Hg

C

97 mm Hg

D

101 mm Hg

Text Solution

Verified by Experts

The correct Answer is:
b
According to Raoult's Law
`(P_(A)^(@)-P_(S))/P_(S)="i"n_(B)/n_(A)`
`AB_(2)overset((aq))toA^(+)(aq)+2B^(-)(aq)`
`i=(1-alpha+nalpha)/1=(1-1+3xx1)/1=3`
`P_(S)^(@)/P_(S)=1+0.03=1.03`
`P_(S)=P_(A)/(1.03)=((100mm))/((1.03))=97.0mm`
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