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A dry air is passed through a soution wh...

A dry air is passed through a soution which contains 10 g of a solute dissoved in 90 g of water. Then the same air is passed through pure water. The depression in weight of the solution is by 2.5 g and in weight of pure solvent (i.e. water) is 0.05 g. The molar mass of the solute is :

A

25

B

50

C

100

D

180

Text Solution

Verified by Experts

The correct Answer is:
c
According to Raoult's Law
`(P_(A)^(@)-P_(S))/P_(S)=("Lowring in weight of solvent")/("Lowring in weight of solution")=((0.05g))/((2.5g))`
According to Raoult's Law
`(P_(A)^(@)-P_(S))/P_(S)=n_(B)/n_(A)=W_(B)/M_(B)xxM_(A)/W_(A)`
`((0.05))/((2.5))=((10g))/((M_(2)))xx((18g mol^(-1)))/((90g))`
`M_(2)=((10g)xx(18gmol^(-1))xx2.5)/((0.05)xx(90g))=100 g mol^(-1)`
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