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The molal freezing point constant for wa...

The molal freezing point constant for water is `1.86^(@)C//m`. Therefore, the freezing point of 0.1 M NaCl solution in water is expected to be:

A

`-1.86^(@)C`

B

`-0.186^(@)C`

C

`-0.372^(@)C`

D

`+0.372^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
c
`DeltaT_(f)=iK_(f)m=2xx1.86^(@)C//mxx0.1m`
`=0.372^(@)C`
`F.P.=0-0.372^(@)C=-0.372^(@)C`
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