v1_newFlow

A

`i=(1-alpha)`

B

`i=(1+alpha)`

C

`i=(1-alpha//2)`

D

`i=(1+alpha//2)`

Text Solution

Verified by Experts

The correct Answer is:
c

`2C_(6)H_(5)COOHhArr(C_(6)H_(5)COOH)_(2)`
For association,
`alpha=((i-1))/((1//n-1))=((i-1))/((1//2-1))`
`-alpha//2=i-1or i=(1-alpha//2)`
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