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The mole fraction of a solute in bezene ...

The mole fraction of a solute in bezene solvent is 0.2. The molality of the solution will be:

A

14

B

3.2

C

1.4

D

2

Text Solution

Verified by Experts

The correct Answer is:
b
`X_(B)=n_(B)/(n_(B)+n_(A))`
`0.2=n_(B)/(n_(b)+1000//78)`
`1/0.2=(n_(B)+12.82)/n_(B)`
`5=1+(12.82)/n_(B)n_(B)=(12.82)/4=3.2` (Mass of solvent is 1000 g)
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