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In a 0.2 molal aqueous solution of a wea...

In a 0.2 molal aqueous solution of a weak acid HX the degree of ionization is 0.3. Taking `K_(f)` for water as 1.85, the freezing point of the solution will be nearest to

A

`-0.360^(@)C`

B

`0.260^@)C`

C

`+0.480^(@)C`

D

`0.480^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
d
`alpha=(i-1)/(n-1)or 0.3=(i-1)/(2-1)`
i=1.3.
`DeltaT_(f)=iK_(f)m`
`=1.3xx(1.85 K kg mol^(-1))xx(0.2 mol kg^(-1))`
=0.480 K.
f.p. of solution = 0-0.480 K.
`=-0.480K=-0480^(@)C`.
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