Home
Class 12
CHEMISTRY
6.02 xx 10^(20) molecules of urea are pr...

`6.02 xx 10^(20)` molecules of urea are present in 100 mL of its solution. The concentration of urea solution is
(Avogadro constant, `N_(A) = 6.02 xx 10^(23)mol^(-1))`

A

0.02 M

B

0.01 M

C

0.001 M

D

0.1 M Glucose.

Text Solution

Verified by Experts

The correct Answer is:
b
`"No. of moles of urea"=(6.02xx10^(20))/(6.02xx10^(23))`
=0.001 mol.
100 mL of solution has moles = 0.001
1000 mL of solution has moles
`=(0.001)/((10mL))xx(1000mL)=0.01 M.`
Doubtnut Promotions Banner Mobile Dark
|

Similar Questions

Explore conceptually related problems

6.02xx10^(23) molecules of urea are present in 100 ml of its solution. The concentration of urea solution is -

6.02 xx 10^(20) molecules of urea are present in 100 mL of its solution. The concentration of solution is

Knowledge Check

  • 6.022 xx 10^(20) molecules of urea are present in 100 mL of its solution. The concentration of urea solution is :

    A
    0.001 M
    B
    0.01 M
    C
    0.02 M
    D
    0.1 M

  • 6.02 xx 10^(21) molecules of urea are present in 100ml of its solution. The concentration of urea solution is

    A
    `0.001 M`
    B
    `0.01 M`
    C
    `0.02 M`
    D
    `0.1 M`

  • 6.02 xx 10^(21) molecules of urea are present in 100ml of its solution. The concentration of urea solution is

    A
    `0.001M`
    B
    `0.01M`
    C
    `0.02M`
    D
    `0.01M`

    • Similar Questions

    Explore conceptually related problems

    6.02xx10^(20) molecules of urea are present in 100 mL of its solution. The concentration of the solution is

    6.02 xx10^(20) molecules of urea are present in I 00 ml of its solution. The concentration of urea solution is

    6.0xx10^(20) molecules of urea are present in 100 L of his solution. The concentration of urea solution is

    6.02xx10^(20) molecules of urea are present in 100 mL of its solution. The concentration of the solution is

    6.02xx10^(20) molecules of urea are present in 100 ml of its solution. The concentration of solution is :

    Home
    Profile