`6.02 xx 10^(20)` molecules of urea are present in 100 mL of its solution. The concentration of urea solution is
(Avogadro constant, `N_(A) = 6.02 xx 10^(23)mol^(-1))`

Options

A. 0.02 M
B. 0.01 M
C. 0.001 M
D. 0.1 M Glucose.

Answer

b

Explanation

`"No. of moles of urea"=(6.02xx10^(20))/(6.02xx10^(23))`
=0.001 mol.
100 mL of solution has moles = 0.001
1000 mL of solution has moles
`=(0.001)/((10mL))xx(1000mL)=0.01 M.`