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To neutralize completely 20 mL of 0.1M a...

To neutralize completely 20 mL of 0.1M aqueous solution of phosphorus acid `(H_(3)PO_(3))` the volume of `0.1M` aqueous KOH solution required is

A

40 mL

B

20 mL

C

10 mL

D

60 mL

Text Solution

Verified by Experts

The correct Answer is:
a
Since `H_(3)PO_(3)` is dibasic, 0.1 M solution =- 0.2 N solution.
`underset(("Acid"))(N_(1)V_(1))=underset(("Base"))(N_(2)V_(2))`
`(0.2 N)xx20 mL)=(0.1N)xxV_(2)`
`V_(2)=((0.2N)xx(20mL))/((0.1N))=40 mL.`
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