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Density of 2.05 M solution of acetic aci...

Density of `2.05 M` solution of acetic acid in water is `1.02g//mL`. The molality of same solution is:

A

1.14 m

B

3.28 m

C

2.28 m

D

0.44 m

Text Solution

Verified by Experts

The correct Answer is:
c
2.05 M solution of acetic acid means that `(2.05xx60=123 g)` of acid is present in 1000 mL of solutiion
Mass of solution=`Vxxd`
=`(1000mL) xx (1.02 g mol^(-1))`
=1020 g
`"Mass os solvent"= 1020-123=897 g.`
`"Molality (m)"=((2.05 mol))/((0.897 kg))`
`=2.28 mol kg^(-1)=2.28 m`
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