Home
Class 12
CHEMISTRY
The vapour pressure of water at 20^(@)C ...

The vapour pressure of water at `20^(@)C` is 17.5 mm Hg. If 18 g of glucose `(C_(6)H_(12)O_(6))` is added 178.2 g of water at `20^(@)C`, the vapour pressure of the resulting solution will be :

A

17.325 mm Hg

B

17.675 mm Hg

C

15.750 mm Hg

D

16.500 mm Hg

Text Solution

Verified by Experts

The correct Answer is:
a

According to Raoult's Law.
`P_(A)=P_(A)^(@)X_(A)`
`X_(A)=n_(A)/(n_(A)+n_(B))=((178.2)/18)/((188.2)/18+18/180)`
`=(9.9)/(9.94)=0.99`
`P_(A)=(17.5mm)xx0.99=17.32 mm`
Promotional Banner

Similar Questions

Explore conceptually related problems

The vapour pressure of water at 20^(@) C is 17.5 mm Hg. If 18 g of gulucose (C_(6)H_(12)O_(6)) is added to 178.2 g of water at 20^(@) C, the vapour pressure of the resulting solution will be:

The vapour pressure of water at 20^(@) is 17.5 mmHg . If 18 g of glucose (C_(6)H_(12)O_(6)) is added to 178.2 g of water at 20^(@) C , the vapour pressure of the resulting solution will be

The vapour pressure of water at 25^(@)C is 18 mmHg. If 18 g of glucose (C_(6)H_(12)O_(6)) is added to 178.2 g of water at 20^(@)C , the vapour pressure of the resulting solution will be :

The vapour pressure of water at 20^@C is 17.5mmHg .if 18g of glucose (C_(6)H_(12)O_(6) is added to 178.2g of water at 20^@C , the vapour pressure of the resulting solution will be,

18 g of glucose (C_(6)H_(12)O_(6)) is added to 178.2 g of water. The vapour pressure of water for this aqueous solution at 100^@C is :

18g of glucose (C_(6)H_(12)O_(6)) is added to 178.2g of water. The vapour pressure of water for this aqueous solution at 100^(@)C