The volume of water to be added to 100 mL of 0.5N `H_(2)SO_(4)` acid solution to get solution of decinormal concentration is :

Options

A. 400 mL
B. 450 nL
C. 500 mL
D. 100 mL

Answer

a

Explanation

`N_(1)V_(1)=N_(2)V_(2)`
`(0.5 N)xx(100mL)=(0.1 N)xxV_(2)`
`V_(2)=((0.5N)xx(100mL))/((0.1N))=500 mL`
Volume of water to be added=(500-100)=400 mL