Home
Class 12
CHEMISTRY
The vapour pressure of pure benzene and ...

The vapour pressure of pure benzene and pure toluene at a particular temperature are 100 mm and 50 mm repectively. The mole fration of benzene in the vapour phase in contact with equimolar solution os benzene and toluene is:

A

0.67

B

0.75

C

0.33

D

0.5

Text Solution

Verified by Experts

The correct Answer is:
a

For equimole solutions, `X_(B)=X_(f)=0.5`
`P_(B)=X_(B)xxP_(B)^(@)=0.5xx100=500mm`
`P_(T)=X_(T)xxP_(T)=0.5xx50-25 mm`
`"Total vapour pressure "(P_("Total")=75mm`
Mole fraction of benzene in the vapour phase=
`P_(B)/_("Total")=50/75=2/3=0.67.`
Promotional Banner

Similar Questions

Explore conceptually related problems

The vapour pressure of pure benzene and toluene are 160 and 60 mm Hg respectively. The mole fraction of benzene in vapour phase in contact with equimolar solution of benzene and toluene is :

The vapour pressure of pure benzene and toluene are 160 and 60 torr respectively. The mole fraction of toluene in vapour phase in contact with equimolar solution of benzene and toluene is:

Equal moles of benzene and toluene are mixed. The vapour pressure of benzene and toluene in pure state are 700 and 600 mm Hg respectively. The mole fraction of benzene in vapour state is :-

Benzene and naphthanlene form idal solution over the entire range of compostion. The vapour pressure of pure benzene and naphthalene at 300 K are 50.71 mm Hm and 32.06 mm Hg respectively. Calculate the mole fraction of benzene in vapour phase if 80 g of benzene is mexed with 100 g of naphthalene.