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The elevation in boiling point of a solu...

The elevation in boiling point of a solution of `13.44`g of `CuCl_(2)`(molecular weight =`134.4,k_(b)=0.52K "molality"^(-1))` in `1` kg water using the following information will be:

A

`0.16`

B

`0.05`

C

`0.1`

D

`0.2`

Text Solution

Verified by Experts

The correct Answer is:
a
`{:((a),CuCI_(2),hArr,Cu^(2+),+,2CI^(-)),("Initial",CuCI_(2),,0,,0),("molar conc",,,,,1),("Eqm.molar",,,,,),("conc",(1-alpha),,alpha,, 2alpha):}`
`i=(1-alpha)+alpha+2alpha=1+2alpha`
Assuming 100% dissociation `(alpha=1)`
`i-1+2xx1=3`
`DeltaT_(b)=ixxK_(b)xxm`
`=(3xx(0.52"K kg mol"^(-1))xx(13.44g))/((134.4 "g mol"^(-1))xx(1 kg))`
`=0.156 K ~~0.16 K`
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