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A compound MX(2) with molar mass of 80 ...

A compound `MX_(2)` with molar mass of 80 g is dissolved in a solvent having density 0.4 g `mL^(-1)`. Assuming that there is no change in volume upon dissociation, what is the molality of a 3.2 molar solution ?

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3.2 mola solution contains solute=3.2 mol
Consider that the volume of solution =1L
Since there is no change in volueme,
on dissolution of the solvent, volume solvent = 1L
Mass of the solvent = `vxxd`
=`(100mL)xx(0.4 mg L^(-1))=400 g=0.4 kg`
`("Molality of solution")=("No. of moles of solute")/("Mass of solvent in kg")`
`=((3.2mol))/((0.4 kg))=8 "kg mol"^(-1)=8` molal
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