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An oil drop has 8.0 xx 10^(-19)C charge....

An oil drop has `8.0 xx 10^(-19)C` charge. How many electrons does this oil drop has?

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Charge on the oil drop `=8.0 xx 10^(-19)C`
Charge on the electron `= 1.6 xx 10^(-19)C`
we know that `q = n e, n = (q)/(e) = (8 xx 10^(-19))/(1.6 xx 10^(-19))=5`
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